leap day: n. 闰日(指2月29日) 英语新词汇与常用词汇的翻译(79) - 词汇 翻译... ... leap at 欣然接受 leap day 闰日 leap out 引人注意 ... 例句与用法： 1. Leap-year day(every four years) and year-end day(every year) would be counted as extra Saturdays. 人们把闰年日（每四年一天）和年末日（每年一天）视为外加的星期六。 2. Rejoice in that day and leap for joy, for behold, your reward is great in heaven; for so their fathers did to the prophets. 23当那日你们要欢喜跳跃，因为看哪，你们在天上的赏赐是大的，原来他们的祖宗待申言者也是这样。 3. "Rejoice in that day and leap for joy, because great is your reward in heaven. For that is how their fathers treated the prophets. 23当那日你们要欢喜跳跃。因为你们在天上的赏赐是大的。他们的祖宗待先知也是这样。 4. Lk. 6:23 Rejoice in that day and leap for joy, for behold, your reward is great in heaven; for so their fathers did to the prophets. 路六23当那日你们要欢喜跳跃，因为看哪，你们在天上的赏赐是大的，原来他们的祖宗待申言者也是这样。 5. "Be glad in that day and leap for joy, for behold, your reward is great in heaven. For in the same way their fathers used to treat the prophets. 路6:23当那日你们要欢喜跳跃．因为你们在天上的赏赐是大的．他们的祖宗待先知也是这样。
3，229女生的表白日
leap day 是英国的一个节日 在这天女生可以向男生表白的 如果男生不同意 就送女生一件 silk dress.拐女生的!没有定义!最起嘛我这个女生没收到消息!只是为了替女生找个表白的机会!我可没有听过啊！
假的~ 呵呵``
#includevoid main() { int y,m,d,sum,i; int month[]={0,31,28,31,30,31,30,31,31,30,31,30,31}; while((scanf("%d/%d/%d",&y,&m,&d))!=EOF) { sum=d; if(y%4==0&&y%100!=0||y%400==0) month[2]=29; else month[2]=28; for(i=1;i sum+=month[i]; printf("%d\n",sum); } } 具体思路就是这样子#include#include int leap(void) { int year; bool r; printf("Enter a year: "); scanf("%d", &year); printf("\n"); if(year%4==0 && year%100
6，海阔任鱼跃天高任鸟飞的意思是什么
呵呵，就是可以一展宏图的意思属于比较能励志的诗句了出处： 宋·阮阅《诗话总龟前集》卷三十引《古今诗话》谓：唐代大历年间，禅僧元览在竹上题诗：“大海从鱼跃，长空任鸟飞。”这句诗表达出禅僧自由自在的广阔胸襟和活泼泼的禅机。后改变为“海阔凭鱼跃，天空任鸟飞”，比喻可以充分自由地行动，或无拘无束地施展才能。如《西游记》第八四回：“老菩萨，古人云：海阔凭鱼跃，天空任鸟飞。怎么西进便没路了？”又如于逢《金沙洲》第三部九：“啊！海阔任鱼跃，天空任鸟飞，谁还愿意待在一个村子里呢！”亦缩为“海阔天空”。如清·蒋士铨《一片石·宴阁》：“共记滕王阁下时，海阔天空任所之。”今亦比喻话说得漫无边际。如夏衍《上海屋檐下》第一幕：“过一会儿姓林的走过来，话又会讲不完啦，海阔天空的。”只要有能力，你的发挥程度是无法限量的简单直白就是：世界很大，你可以勇敢的创大海从鱼跃，长空任乌飞。——唐（僧）玄览 [解读] 这两句是佛门用来比喻人应心胸开阔，无拘无束，有一种超尘世的精神境界。现在常说“海阔凭鱼跃，天高任鸟飞” （《西游记》第八十三回），用来形容英雄有用武之地，在广阔天地里，大显身手，充分发挥聪明才智，或者比喻议论没有中心，漫无边际。语云：“海阔凭鱼跃，天高任鸟飞。”事实上不是所有的鱼都能在海里跳跃，所有的鸟都可在天上飞。The sea is extravagant no matter what fish leap,Day Gao Renniao flies
7，用C语言函数输入某年某月某日判断这一天是这一年的第几天 搜
好深奥啊！short finddays(short year, short month, short day) short toReturn = day; switch (month) case 12:toReturn += 30; case 11:toReturn += 31; case 10:toReturn += 30; case 9:toReturn += 31; case 8:toReturn += 31; case 7:toReturn += 30; case 6:toReturn += 31; case 5:toReturn += 30; case 4:toReturn += 31; case 3:toReturn += (year % 4 ? 28 : 29); case 2:toReturn += 31;break; default:break; } return toReturn;}/* GCC3.4下测试通过 *//* 自己加入判断月日是否合法 */你的函数h（day）只传入一个参数，怎么计算天数呢？改成3个参数就可以直接返回了int h（int year;int month,int day） int a[13]= int s=0,i; for(i=0;i<month;i++) s=s+a[i]; if((year%4==0&&year%100!=0||year%400==0)&&month>2) return s+day+1; else return s+day;}|#include <stdio.h>#include <stdlib.h>static int daytable[2][13] = };/* Get the days from year month day */void get_day ( int year, int *dayofyear, int month, int day ) int i, leap; leap = (( year % 4 == 0 ) && ( year % 100 != 0 ) || ( year % 400 == 0 )); *dayofyear = 0; for (i=1;i< month;i++) *dayofyear = *dayofyear + daytable[leap][i]; } *dayofyear = *dayofyear + day; }void main()int year,month,day;int days;printf("Enter the year month day (for example: 2008 3 1)\n");scanf("%d %d %d",&year,&month,&day);(void) get_day ( year, &days, month, day );printf("the days=%d\n",days);}你的函数h（day）只传入一个参数，怎么计算天数呢？改成3个参数就可以直接返回了inth（intyear;intmonth,intday）inta[13]=ints=0,i;for(i=0;i<month;i++)s=s+a[i];if((year%4==0&&year%100!=0||year%400==0)&&month>2)returns+day+1;elsereturns+day;}
8，c语言编程 万年历查询系统
按你的要求写的 如果不能正常运行联系我
#include <stdio.h>#include <stdlib.h>
bool isLeapyear( int nowYear );int calcuWeek( int totalDays );int calcuDays( int nowYear,int nowMonth,int nowDay );bool checkValid( int nowYear,int nowMonth,int nowDay );void nowMonthprint( int nowYear,int nowMonth,int nowDay );void weekDayPrint( int nowYear,int nowMonth,int nowDay );void nowYearprint( int nowYear );void menuPrint();
const int leapDay[12]=const int noleapDay[12]=
int main() int year,month,day; while( true ) menuPrint(); int op; scanf("%d",&op); switch( op ) case 1: printf("请输入年月日（格式为YYYY-MM-DD）："); scanf("%d-%d-%d",&year,&month,&day); if ( checkValid(year,month,day) ) weekDayPrint(year,month,day); else printf("输入错误!!!退出操作\n"); break; } break; } case 2: printf("请输入需要查询的年份："); scanf("%d",&year); if( year > 9999 || year < 0 ) printf("年份输入错误!!!退出操作\n\n"); break; } if ( isLeapyear( year ) ) printf("%-4d年是闰年！！！\n\n",year); else printf("%-4d年是平年！！！\n\n",year); break; } case 3: printf("请输入需要查询的年份："); scanf("%d",&year); if( year > 9999 || year < 0 ) printf("年份输入错误!!!退出操作\n\n"); break; } nowYearprint(year); break; case 4: printf("请输入年月日（格式为YYYY-MM-DD）："); scanf("%d-%d-%d",&year,&month,&day); if ( checkValid(year,month,day) ) nowMonthprint(year,month,day); else printf("输入错误!!!退出操作\n"); break; } break; case 5: int maxdays; printf("请输入需要查询的年份及月份（格式YYYY-MM）："); scanf("%d-%d",&year,&month); if( year > 9999 || year < 0 || month > 12 || month < 0 ) printf("年份及月份输入错误!!!退出操作\n\n"); break; } if ( isLeapyear(year)) maxdays = leapDay[month-1]; else maxdays = noleapDay[month-1]; printf("%d年%d月最大天数为%d\n\n",year,month,maxdays); break; case 6: printf("退出系统，谢谢使用\n\n"); return 0; break; } } return 0;}
bool isLeapyear( int nowYear ) // 判断是否闰年 if( nowYear%4 == 0 && nowYear%100 != 0 || nowYear%400 == 0) return true; else return false;}
bool checkValid( int nowYear,int nowMonth,int nowDay )// 输入合法性检查 if ( nowYear <= 0 ) printf( "输入年份不合法！！！"); return false; } if ( nowMonth < 0 && nowMonth > 12 ) printf("输入月份不合法！！！"); return false; } if ( nowDay < 0 && nowDay > 31 && isLeapyear(nowYear) ) printf("输入号数不合法！！！"); return false; } if ( nowDay < 0 && nowDay > 30 && !isLeapyear(nowYear) ) printf("输入号数不合法！！！"); return false; }
return true;}
int calcuDays( int nowYear,int nowMonth,int nowDay )// 计算总天数 int days = 0; int mon = 0; for ( int i = 1;i < nowYear;i++ ) if( isLeapyear( i ) ) days += 366; else days += 365; } for ( int j = 1;j < nowMonth;j++ ) if ( isLeapyear(nowYear) ) mon = mon + leapDay[j-1]; else mon = mon + noleapDay[j-1]; } days = days + mon + nowDay;
return days;}
int calcuWeek( int totalDays ) // 计算星期几 int weekNo = totalDays%7; return weekNo;}
void weekDayPrint( int nowYear,int nowMonth,int nowDay ) //打印某年某日星期几 int days = calcuDays(nowYear,nowMonth,nowDay); int weekNo = calcuWeek( days ); switch ( weekNo ) case 0: printf( "%-4d年%-2d月%-2d日是星期天！！！",nowYear,nowMonth,nowDay); break; case 1: printf( "%-4d年%-2d月%-2d日是星期一！！！",nowYear,nowMonth,nowDay); break; case 2: printf( "%-4d年%-2d月%-2d日是星期二！！！",nowYear,nowMonth,nowDay); break; case 3: printf( "%-4d年%-2d月%-2d日是星期三！！！",nowYear,nowMonth,nowDay); break; case 4: printf( "%-4d年%-2d月%-2d日是星期四！！！",nowYear,nowMonth,nowDay); break; case 5: printf( "%-4d年%-2d月%-2d日是星期五！！！",nowYear,nowMonth,nowDay); break; case 6: printf( "%-4d年%-2d月%-2d日是星期六！！！",nowYear,nowMonth,nowDay); break; } printf("\n\n");}
void nowMonthprint( int nowYear,int nowMonth,int nowDay ) // 打印月历 int monthDay; int days = calcuDays(nowYear,nowMonth,1); int weekNo = calcuWeek(days); if ( isLeapyear(nowYear) ) monthDay = leapDay[nowMonth-1]; else monthDay = noleapDay[nowMonth-1];
printf( "-----------------%4d年%02d月---------------\n",nowYear,nowMonth ); printf( "%-5s%-5s%-5s%-5s%-5s%-5s%-5s\n","天","一","二","三","四","五","六" );
for ( int j = 1; j <= monthDay; j++ ) if ( j == 1) for ( int k = 0;k < weekNo;k++ ) printf("%-5s"," "); } if ( nowDay == j ) printf("*%-4d",j ); else printf( "%-5d",j); if ( weekNo%7 == 6 ) printf("\n"); weekNo = calcuWeek(days+j) ; } printf("\n");}
void nowYearprint( int nowYear ) // 打印年历 int monthDay; for ( int i = 0; i < 12; i++ ) int days = calcuDays(nowYear,i+1,1); int weekNo = calcuWeek(days); if ( isLeapyear(nowYear) ) monthDay = leapDay[i]; else monthDay = noleapDay[i]; printf( "-----------%4d年%02d月-----------\n",nowYear,i+1 ); printf( "%-5s%-5s%-5s%-5s%-5s%-5s%-5s\n","天","一","二","三","四","五","六" ); for ( int j = 1; j <= monthDay; j++ ) if ( j == 1) for ( int k = 0;k < weekNo;k++ ) printf("%-5s"," "); } printf( "%-5d",j); if ( weekNo%7 == 6 ) printf("\n"); weekNo = calcuWeek(days+j) ; } printf("\n"); }}void menuPrint() // 打印系统菜单 printf("\t万年历查询系统\n"); printf("\n******************************"); printf("\n1.查询某年某月某日是星期几"); printf("\n2.查询某年是否是闰年"); printf("\n3.打印某年的年历"); printf("\n4.打印某年某月的月历"); printf("\n5.查询某月的最大天数"); printf("\n6.退出"); printf("\n*****************************\n"); printf("\n请选择：");}刚刚好有一个,楼主参考一下吧.
如果觉得可以的话,可以留个邮箱,
代码太长,不可以复制到答案里面.
两百分，就两天后给你，这个代码有点多 而且你没说日历的时间范围是多少
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